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2018版高考英语大一轮复习Unit3Ahealthylife复习练案新人教版选修6

2018版高考英语大一轮复习Unit3Ahealthylife复习练案新人教版选修6
2018版高考英语大一轮复习Unit3Ahealthylife复习练案新人教版选修6

Unit 3 A healthy life

Ⅰ.阅读理解

(2016·江西九校联合测试)导学号 42492609

More than 4 in 10 cancers—600,000 in the UK alone—could be prevented if people led healthier lives, say experts.The population of the UK is about 63,000,000.

Latest figures from Cancer Research UK show smoking is the biggest avoidable risk factor (因素), followed by unhealthy diets.The charity advises people to live healthily, limit alcohol intake and do regular exercise.

According to the figures from 2007 to 2011, more than 300,000 cases of cancer recorded were linked to smoking.A further 145,000 were linked to unhealthy diets containing too much processed food.Obesity contributed to 88,000 cases and alcohol to 62,200.Sun damage to the skin and physical inactivity were also contributing factors.

Professor Max Parkin, a Cancer Research UK statistician, says, “There's now little doubt that certain lifestyle choices can have a big influence on cancer risk, with research around the world all pointing to the same key risk factors.”

“Of course every one wants to enjoy some extra treats during the Christmas holidays so we don't want to ban beef pies and wine but it's a good time to think about taking up some healthy habits.”

“Leading a healthy lifestyle can't guarantee someone won't get cancer but we_can_stack_the_ odds_in_our_favour by taking positive steps.”

Public Health England says a healthy lifestyle can play an important role in reducing cancer risk.It says campaigns such as Smokefree, Dry January and Change Life Sugar Swaps all aim to raise public awareness.It's important that we not only continue to make progress in noticing cancer earlier and improving treatments, but helping people understand how they can reduce their risk of developing cancer in the first place remains important in dealing with cancer.

文章大意:本文是一篇说明文。专家们认为,如果我们拥有健康的生活方式,那么超过十分之四的癌症是可以避免的。

1.Which of the following is the third biggest avoidable cancer factor?__A__ A.Obesity. B.Alcohol intake.

C.Unhealthy diets. D.Physical inactivity.

解析:细节理解题。根据第三段内容可知,可避免的致癌因素中排名第一的是吸烟,第二是不健康的饮食,第三是肥胖,第四是喝酒。

2.According to Professor Max Parkin,__A__.

A.it's OK to drink wine during festivals

B.the causes of cancer are still unclear now

C.unhealthy food should be completely banned

D.a healthy lifestyle will protect us from cancer

解析:细节理解题。根据第五段中的“every one wants to enjoy some extra treats during the Christmas holidays so we don't want to ban beef pies and wine”可知,Max Parkin教授虽然极力倡导健康的生活方式,但他认为节假日期间少量喝酒还是可以的。

3.By saying the underlined words in Paragraph 6,Professor Max Parkin means we can__D__.

A.help others

B.improve our lives

C.discover cancer early

D.decrease our cancer risk

解析:句意理解题。根据第四段中的“certain lifestyle choices can have a big influence on cancer risk”可知,生活方式的选择对得癌症的几率有很大的影响。因此,健康的生活方式虽然不能确保我们不得癌症,但可以“降低我们得癌症的几率”。

4.What's the main idea of the text?__B__

A.Most cancers are caused by smoking.

B.Cancer is greatly linked to our lifestyle.

C.There are different factors that lead to cancer.

D.Public awareness should be raised to prevent cancer.

解析:主旨大意题。本文前三段通过数据等说明可避免的致癌因素的前几名都跟生活方式有关,第四、五、六段引用Max Parkin教授的话进一步证明了生活方式与癌症之间的关系,最后一段通过英国公共卫生局的官方发言再一次说明了健康的生活方式可以降低得癌症的几率。故选B项。

Ⅱ.七选五导学号 42492610

根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。选项中有两项为多余选项。

(2016·四川)

Both men and women are living longer these days in industrialized

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→exactly adv. 确实如此;正是;确切地15.agree vi. 同意 →agreement n. 协议;同意;一致 →disagree vi. 不同意 16.like vt. 喜欢 prep. 像;如同 →dislike n.&vt. 不喜欢;厌恶17.outdoor adj. 户外的;室外的 →outdoors adv. 在户外;在野外 n. 野外;郊外 →indoors adv. 在室内;进入户内 Ⅱ.阅读单词——要识记 18.curtain n.窗帘;门帘;幕布19.series n. 连续;系列 20.thunder vi. 打雷;雷鸣 n. 雷;雷声 21.tip n. 提示;技巧;尖;尖端;小费vt. 倾斜;翻倒 22.partner n. 伙伴;合作者;合伙人23.highway n. 公路;大路 24.item n. 项目;条款 25.swap vt.交换 高频短语——会默写 1.add up 合计 2.calm(...)down (使)平静下来;(使)镇定下来3.be concerned about 关心;挂念 4.go through 经历;经受;完成;仔细检查5.set down 记下;放下;登记 6.a series of 一连串的;一系列;一套7.on purpose 故意地;有目的地 8.at dusk 在黄昏时刻 9.face to face 面对面地

2018届一轮复习人教版 植物的激素调节 教案

讲考纲 讲考点 考点一植物生长素的发现和作用1.生长素的发现过程

2.生长素的产生、运输和分布 (1)产生部位:主要在幼嫩的芽、叶和发育中的种子。 (2)运输:极性运输(胚芽鞘、芽、幼叶和幼根),方向从形态学上端运输到形态学下端;非极性运输:在成熟组织中,可以通过韧皮部进行 (3)分布部位:相对集中地分布在生长旺盛的部分。 3.生长素的生理作用 (1)作用特点:两重性——既能促进生长,也能抑制生长。 (2)实例剖析 ①顶端优势 a.概念:植物的顶芽优先生长而侧芽受到抑制的现象。 b.原因: c.解除方法:摘除顶芽。 d.应用:可适时摘除棉花的顶芽,解除顶端优势,以促进侧芽的发育,从而使它多开花、多结果。 ②根的向地性 重力→生长素分布不均(向地侧生长素浓度高,背地侧生长素浓度低)→生长不均(根的向地侧生长慢,背地侧生长快)→根向地生长。 ③除草剂

从图中可以看出,双子叶植物比单子叶植物敏感。用适当浓度的生长素类似物来杀死单子叶农田里的双子叶杂草,同时促进单子叶植物的生长。 【例1】(2017年江苏卷,13)研究小组探究了萘乙酸(NAA)对某果树扦插枝条生根的影响,结果如下图。下列相关叙述正确的是() A.自变量是NAA,因变量是平均生根数 B.不同浓度的NAA 均提高了插条生根率 C.生产上应优选320 mg/ L NAA 处理插条 D.400 mg/ L NAA 具有增加生根数的效应 【答案】D 【跟踪训练1】图甲为横放在地面上的幼苗生长状况,图乙为不同浓度的生长素对植物生长影响曲线。下列分析正确的是()

A.用B、D点所对应浓度的生长素处理扦插枝条则生根效果不相同 B.若某植物幼苗向光侧的生长素浓度为f,则背光侧的生长素浓度可能大于2f C.图甲中a、b、c、d四点的生长素浓度大小为a>c、d>b D.若图甲中b点的生长素浓度与图乙中B点对应的浓度相同,则d点的生长素浓度在BD对应的浓度区间 D 【答案】 1.其他植物激素的种类及作用 2.五种植物激素对应的生长调节剂的应用

2018年高考英语天津专版复习:专题一 语法知识 第一讲 含答案

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解析句意为:当我们学会求同存异,而非对立分歧时,我们会收获颇多。divide分开,使产生分歧;reject拒绝;control控制;abandon放弃,抛弃。根据句意可知选A。 3.Shakespeare’swritingisstillpopulartoday.Ithasreally________thetestof time. (2014·安徽,34) A.failed B.stood C.taken D.conducted 答案 B 解析考查动词辨析。句意为:莎士比亚的作品现在依然流行,它真的已经经受住了时间的考验。由句意可知选B。 考点归纳 熟词生义现象在高考中屡屡出现,有时会给考生带来不小的困难。应对的措施是在日常的学习备考中对常见的词汇除了掌握其基本意义外,对其不太常用的义项也要作适当的了解;其次要对一些具有“熟词生义”的词汇作强化记忆处理,以便在应考时做到胸有成竹。如下列单词的“熟词生义”: ache渴望;address在……上写地址,演说;alone只有;appreciate意识到;blue忧伤的;count有价值;cover够……用;develop逐渐形成;draw推断出;date约会;escape被忘掉;fail使失望,衰竭;foreign不熟悉的;fresh 无经验的;ground理由;invite招致;late已故的;might力量;observe遵守,庆祝;push督促;promise预示;part分手,放弃;read写着;relate讲述;say假设;subject易遭受……的;walk遛等。

2018(江苏)高考英语一轮复习教案:1.2(b)经典句型 含答案

2018(江苏)高考英语一轮复习教案:1.2(b)经典句型 江苏高考英语一轮复习教案:1.2(b)经典句型 ●模块一Unit 2 一、高考能力提升练习 【一】阅读理解 I shall never forget the day when the earthquake took place.The time was about 5 o’clock in the afternoon and I was driving along the road to take my daughter from school.Our plan was to go swimming together.I had finished my work at 4 o’clock and then gone to the Post Office.Then I stopped off at a shop in order to get some fresh fruit.We liked to have some fruit to eat after our swim. I was driving along a high road on my way to my daughter’s school.Over my road was another road which was built like a bridge for cars coming to the other way.I was hungry so I put the bag of apples in the seat beside me and started to eat one. Suddenly I saw the cars in front of me start to move from side to side.Then my car started to shake!I didn’t know what was happening.Perhaps something had gone wrong with my car.I drove a little more slowly and then I stopped the car and at the same moment the road fell onto the car in front of me. I found myself in the dark.I couldn’t move.The bottom parts of both of my legs and my feet were hurting badly and I couldn’t move them.All around me was quiet.But above me I could hear shouts and a lot of noise.Then I memorized (记起) what had happened.I had been in an earthquake. For about two hours nobody came.Luckily I could reach the bag of apples,so at least I had plenty to eat.Then I heard people climbing towards me.A team of people had come to see if anyone was under the broken road.I called out,“I’m here!” I heard a shout.Soon a stranger climbed to the side of the road near my car.“How are you doing?” he asked.

2018届一轮复习人教版圆周运动教案

第16讲 圆周运动 【教学目标】 1.掌握描述圆周运动的物理量及其之间的关系. 2.理解向心力公式并能应用;了解物体做离心运动的条件. 【教学过程】 ★重难点一、圆周运动的运动学问题★ 1.圆周运动各物理量间的关系 2.对公式v =ωr 的理解 当r 一定时,v 与ω成正比; 当ω一定时,v 与r 成正比; 当v 一定时,ω与r 成反比。 3.对a =v 2r =ω2r 的理解 当v 一定时,a 与r 成反比; 当ω一定时,a 与r 成正比。 4.常见的三种传动方式及特点 (1)皮带传动:如图甲、乙所示,皮带与两轮之间无相对滑动时,两轮边缘线速度大小相等,即v A =v B 。 (2)摩擦传动:如图甲所示,两轮边缘接触,接触点无打滑现象时,两轮边缘线速度大小相等,即v A =v B 。

(3)同轴传动:如图乙所示,两轮固定在一起绕同一转轴转动,两轮转动的角速度大小相等,即ωA =ωB 。 【典型例题】(多选)在汽车无级变速器中,存在如图所示的装置,A 是与B 同轴相连的齿轮,C 是与D 同轴相连的齿轮,A 、C 、M 为相互咬合的齿轮。已知齿轮A 、C 规格相同,半径为R ,齿轮B 、D 规格也相同,半径为1.5R ,齿轮M 的半径为0.9R 。当齿轮M 按如图方向转动时( ) A .齿轮D 和齿轮 B 的转动方向相同 B .齿轮D 和齿轮A 的转动周期之比为1∶1 C .齿轮M 和齿轮C 的角速度大小之比为9∶10 D .齿轮M 和齿轮B 边缘某点的线速度大小之比为2∶3 【答案】ABD 【解析】A 、M 、C 三个紧密咬合的齿轮是同缘传动,因为M 顺时针转动,故A 逆时针转动,C 逆时针转动,又A 、B 同轴转动,C 、D 同轴转动,所以齿轮D 和齿轮B 的转动方向相同,故A 正确;A 、M 、C 三个紧密咬合的齿轮是同缘传动,边缘线速度大小相同,齿轮A 、C 规格相同,半径为R ,根据v =ωr 得,A 、C 转动的角速度相同,A 、B 同轴转动,角速度相同,C 、D 同轴转动,角速度也相同,且齿轮B 、D 规格也相同,所以齿轮D 和齿轮A 的转动角速度相同,故B 正确;A 、M 、C 三个紧 密咬合的齿轮是同缘传动,边缘线速度大小相同,根据v =ωr 得 ωM ωC =r C r M =R 0.9R =109 ,故C 错误;A 、M 、C 三个紧密咬合的齿轮是同缘传动,边缘线速度大小相同,根据v =ωr 得 ωA ωM =r M r A =0.9R R =910,又A 是与B 同轴相连的齿轮,所以ωA =ωB ,所以 ωM ωB =ωM ωA =109 ,根据v =ωr 得 v M v B =ωM r M ωA r B =109×0.9R 1.5R =23 ,故D 正确。 ★重难点二、圆周运动的动力学分析★

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