：英语阅读：如何选择正确的英语课外阅读材料小编给你一个美联英语官方试听课申请链接：
我们常说的英语阅读就是读者利用相关的英语知识和非英语知识去包含一定英语知识和非英语知识的阅读材料。英语知识是指读者英语语音、词汇、语法以及篇章知识的总和，而非英语知识是指读者英语知识以外的背景知识，即直接或间接获取的知识经验的总和。
在培养学生的英语语言综合运用能力听说读写过程中，阅读能力的提高对于英语学习者来说是重中之重。诚如刘润清教授所总结的那样“正式的外语教学与其他学科教学一样，要想真正掌握一门外语，需要大量的阅读，有独立的思维过程和分析总结过程”。
课外阅读是高中英语教学的必要补充。高中英语大纲明确指出：要提高学生的阅读能力，单纯通过教科书的课文教学是远远不够的，还要根据学生的具体情况，有计划地指导学生在课外阅读一定数量的课外读物。理由是：第一，现行的课文教学篇目少，篇幅短，不能保证充分的阅读活动;第二，精读教学担负着语言知识教学的任务，所以，课文生词和新的语言结构的密度大，不适用于流畅阅读的训练;第三，精读实际上综合训练，大量的时间用于为语言点的掌握而安排的听、说、读、写操练上，读的专门训练不够。因此，大纲的指出实际上对我们的外语教师提出了更高的、更全面的要求。
我们的理解是，这里的课外阅读即泛读，让学生独立阅读，但又不是“放羊式”的阅读，而是在教师有计划的指导下进行的课外阅读。因此，我们认为泛读既是阅读材料的问题，也是阅读方法的问题，老师应做到以下几点：
首先，给学生选择时应掌握以下原则：(1)思想性强,内容健康; (2)材料难易适合学生的实际水平; (3)题材涉及面广，材料新颖，具有趣味性; (4)文章体载多样化; (5)语言地道、规
范。
其次，告诉学生泛读不同于精读。泛读力求广泛、大量、快速。阅读重点是针对问题快速地捕捉信息。主要方法和技巧如下：(1)快速阅读、知其大意;(2)根据上下文猜测词义;(3)根据构词法来猜测词义;(4)注意深层意思的理解;(5)把理解题目作为提纲来读(即带着问题阅读)。
再次，文章应多选自英美出版的英语读物。如人物传记、寓言故事、活动记述、社会文化、文史知识、科普小品等。这些阅读文章是对课本内容的扩展与延伸，让学生更详细、更全面地了解课本所学的内容。这样让学生们充分利用好身边的资料，不要盲目去选市场上的资料，既节约了费用，也提高了教材的使用率。
通过科学的，师生会共同感受到：大量的正确的课外阅读，确实会让学生受益匪浅。课外于都可以：1)培养学生的阅读技巧和方法;2)巩固课文中所学的基本语言知识;3)开阔了学生的视野，培养学生们学英语的兴趣;4)通过文学简写本的阅读，提高学生文学欣赏的能力;5)学生潜移默化地受到思想品德的教育;6)阅读的同时如能配上适当的笔头练习，将大大提高学生的书写表达能力;7)在阅读的过程中，回顾和加强了课本所学的单词、短语和重点句型。并且也掌握了大量的生词，开拓了学生的视野，逐渐学会了自我阅读自我学习的好习惯好方法，会让学生受益终生。
美联英语：
Fast Reading Materials for Senior I完形填空（共 20 小题；每小题 1.5，满分 30 分） 阅读下面短文，掌握其大意，然后从 36~55 各题所给的四个选项（A、B、C 和 D）中，选出最佳选项，并在答题卡上将该项涂黑。 While I studied at school, I felt a great difficulty in learning my Latin translations. I was always very 36 in using a dictionary, and 37 it most difficult, while to other boys it seemed no 38 . I formed an alliance（盟友）with a boy in the Sixth Grade .He was very clever and 39 read Latin as easily as English .My friend for his part was almost as 40 troubled by the English essays he had to write for the headmaster as I was 41 these Latin words .We agreed together that he would 42 me my Latin translations and that I should do his essays. The arrangement 43 wonderfully. The headmaster seemed quite 44 with my work, and I had more time to myself in the morning. On the other hand, once a week 45 I had to compose the essays of my friend. For several months no difficulty 46 , but once we were nearly caught out. One afternoon, the headmaster 47 my friend to discuss one essay with him in a lively spirit. “I was interested in this48 you make here. I think you might have gone further .Tell me 49 you had in your mind.” The headmaster continued in this50 for some time to the fear of my friend. However the headmaster, not wishing to 51 an occasion of praise into 52 of fault-finding, finally. 53 him go. He came back to me like a man who had had a very narrow 54 and I made up my mind to make every effort to study my 55 . 36．A．quick B．slow C．hard D．good 37．A．made B．got C．found D．left 38．A．trouble B．difference C．labor D．worry 39．A．might B．would C．should D．could 40．A．very B．little C．much D．few 41．A．for B．by C．in D．to 42．A．change B．take C．forgive D．tell 43．A．worked B．tried C．happened D．developed 44．A．angry B．satisfied C．frightened D．sad 45．A．or so B．or else C．as usual D．as far 46．A．became B．seemed C．lay D．appeared 47．A．called B．taught C．arranged D．sent 48．A．aim B．goal C．point D．opinion 49．A．why B．how C．which D．what 50．A．excitement B．way C．meaning D．disappointment 51．A．turn B．leave C．grow D．become 52．A．none B．one C．either D．some 53．A．ordered B．asked C．took D．let 54．A．surprise B．escape C．hope D．chance 55．A．reading B．writing C．translations D．essays II 阅读理解
V. Reading Comprehension (15%) A It was 3.21 a. m. when nine-year-old Glenn Kreamer awoke to the smell of burning. Except for the crackling （爆裂声）of flames somewhere below there was not a sound in the two-storey house at Baldwin, Long Island. With his father away on night duty at a local factory, Glenn was worried about the safety of his mother, his sister Karen, 14 and his 12-year-old brother Todd. He ran downstairs through the smoke-filled house to push and pull at Karen and Todd until they sat up. Then he helped each on through the house to the safety of the garden. There, his sister and brother, taking short and quick breaths and coughing, collapsed on the lawn. The nine-year-old raced back into the house and upstairs to his mother's room. He found it impossible to wake her up. Mrs. Kreamer, a victim of the smoke, was unconscious, and there was nobody to help Glenn carry her to the garden. But the boy remained calm and, as a fireman said later, "acted with all the self-control of a trained adult." On the bedroom telephone, luckily still working, Glenn called his father and, leaving Mr. Kreamer to telephone the fire brigade and ambulance service, got on with the task of saving his mother. First he filled a bucket with water from the bathroom and threw water over his mother and her bed. Then, with a wet cloth around his head he went back to the garden. He could hear the fire engine coming up, but how would the firemen find his mother in the smoke-filled house where flames had almost swallowed up the ground flo or? Grasping firmly a ball of string from the garage, Glenn raced back into the house and dashed upstairs to his mother's room. Tying one end of the string to her hand he ran back, laying out the string as he went, through the hall and back out into the ga rden. Minutes later he was telling fire chief John Coughlan :"The string will lead you to mother." Mrs. Kreamer was carried to safety as the flames were breaking through her bedroom floor. 71．Why did Glenn run downstairs first? A．He wanted to find out what was happening. B．He was worried about his mother's safety.
《分析化学》阅读材料03 摘自Analytical Chemistry (FECS) ●In the Br?sted-Lowry theory, an acid is a proton donor and a base is a proton acceptor. Each acid is related to its conjugate base and vice versa: Acid = base + proton Therefore, the conjugate base of a strong acid must be a weak base and the conjugate base of a weak acid must be a strong base. Together they form a couple, and an acid without its conjugate base is a meaningless concept. In order to release a proton, the acid must find a base to accept it. In an aqueous solution, the proton, H+, having an extremely small ionic radius, cannot exist as such. It is hydrated, forming the hydronium ion H3O+ and higher hydrates. Thus, an acid-base equilibrium is not a simple dissociation equilibrium, but the result of a proton transfer reaction in which there are at least two reagents and two products. Such a process is also called protolysis. The overall reaction is expressed by: HX + H2O = H3O+ + X-. The overall equilibrium constant is K = [H3O+][X-]/[HX][H2O]. The acid dissociation constant Ka is given by: Ka = K[H2O] = [H3O+][X-]/[HX]. Ka reflects not only the acid strength of HX, but also the base strength of water. This why different acid dissociation constants are observed for the same acid in different solvent. ●Similar proton transfer reactions exist in all solvents possessing proton donor and acceptor properties. Proton transfer reactions are extremely fast. This makes them very suitable for analytical applications and acid-base reactions have found wide use in volumetric methods and other analytical techniques. ●The pH value is a measure for the acidity or basicity of a solution, aqueous or nonaqueous. ●Acid-base indicators are chemical substances with acid-base properties, having different colors in their protonated and deprotonated forms. ● A most important application of acid-base systems is related to the property of such a system to act as a buffer. Many chemical reactions produce protons (in aqueous solutions hydroniums) or hydroxide ions. If these products remain in the system, a corresponding pH change is observed. However, if a buffer is present in the solution it reacts with the liberated hydrogen or hydroxide ions so that only a relative small change of pH occurs. Buffer consist of a mixture of a weak acid and its conjugate base. The most efficient buffer for a given pH consists of a 1:1 ratio of the protonated and deprotonated forms of a weak acid (with pKa = pH). This cannot always be achieved, but if we wish to prepare a solution of a certain pH, we select a weak acid with a pKa value close to the desired pH. Buffer solution resists changes in pH upon adding of strong acids or strong bases. Depending on the relative concentrations of the acid and base forms of the buffer, the system can resist small or large additions of strong acid or base. This buffer capacity is defined as the number of moles of strong acid of base required to change the pH of 1 L of buffer solution by one pH unit. Solutions with high or low pH values, formed as a result of dissolution of large quantities of a strong base or acid, are characterized by a large buffer capacity, although the electrolyte practically consists of only one of the conjugate forms (e.g., HCl or NaOH solutions). ● A general requirement for all volumetric methods is that the titration process is fast and that it proceeds in a definite stoichiometric ratio, the endpoint of the reaction must by easy to detect and the reaction should be specific and not influenced by other constituents of the solution, i.e., there should be no interference. Question: 1. A H3PO4 solution is brought to pH = 7.00 by the addition of NaOH. Calculate the concentration of the various forms of orthophosphate if the total phosphate concentration in buffer is 0.200 mol /L. pKa1 = 2.16, pKa2 = 7.21, pKa3 = 12.32. 2. A buffer solution is prepared from acid, HA, Ka = 5 10-5, and its salt. The concentration of HA in the buffer is 0.25 mol / L. To 100 mL of the buffer added 5.0 mmol of NaOH, and the pH of the resulting solution is 5.60. What was the pH of the original buffer? 3.It is desired to change the pH of 100 mL of 0.100 mol / L HCl from 1.00 to 4.40 by the addition of sodium acetate, CH3COONa3H2O. How much solid sodium acetate salt must be added in grams? Assume no volume change for the solution as the result of the addition. 4.What is the buffer capacity of a solution which is 0.100 mol / L of NH3 and 0.200 of NH4Cl? 5.Calculate the pH of each of the following solution: (a) Water in equilibrium with CO2 of the air; pKa1 = 6.38, pKa2 = 10.25. (b) Water as in part (a) brought to pH = 7.00 with NaOH and allowed to regain equilibrium with CO2. 6. Derive the following expression for the pH at the first stoichiometric point in the titration of a mixture of two weak acid: HA, the stronger, Ka1, concentration C1; HB, the weaker, Ka2, concentration C2: pH = 1/2 (pKa1 + pKa2) – 1/2 lg (C1/C2)
最新中考英语阅读理解练习题 一、初三英语阅读理解（含答案详细解析） 1．阅读理解 Radio and television are very popular in the world today. Millions of people watch TV. Perhaps more people listen to the radio. The TV, of course, is more useful than the radio. On TV you can see and hear what is happening in the world. Now the radio is not disappearing. It's still with us. And the number of listeners is becoming larger. One reason for this is the invention of the transistor（晶体管）radio. The transistor radio is sometimes very small. It is very easy to carry. You can put one in your pocket and listen to it on the bus when you go to work. It is better for blind people. Many old people don't have good sight （视力）to watch TV. When people are working，they can't watch TV but they can listen to music or news over the radio. What's more，the radio is much cheaper than the TV. （1）After the television was invented，people ____. A. think it is unnecessary to use the radio B. don't want to use the radio any more C. are still using the radio D. find the radio is disappearing （2）One of the reasons for the larger number of listeners of the radio is that ____. A. the TV was invented B. the transistor radio was invented C. people don't like watching TV D. millions of people watch TV （3）____ listen to the radio more because their sight isn't good enough. A. Children B. Young people C. Old people D. Adults （4）Usually ____ can be used easily while people are moving or working. A. the radio B. the TV C. both the TV and the radio D. neither the radio nor the TV 【答案】（1）C （2）B （3）C （4）A 【解析】【分析】大意：本文讲述收音机和电视机在世界上的很受欢迎，电视与收音机比，电视更有用，然而收音机由于体积小便宜，便于携带，听众也越来越多，深受老年人喜爱。 （1）细节题。根据Perhaps more people listen to the radio.可知，电视发明后，人们依然使用收音机，故选C。 （2）细节题。根据One reason for this is the invention of the transistor（晶体管）radio. 可知，收音机听众的数量更多其中一个原因是晶体管收音机被发明，故选B。 （3）推断题。根据 Many old people don't have good sight（视力）to watch TV.可知，老年人由于视力不好听广播的人更多，故选C。 （4）细节题。根据When people are working，they can't watch TV but they can listen to music or news over the radio.可知，通常人们移动或者工作时可以听收音机，故选A。 【点评】考查阅读理解。细节题和推断题是阅读理解题中常考题型。细节题需要从文中寻
2020年高三英语材料之阅读理解精品版
高三英语材料之阅读理解 阅读理解1 A Besides entertainment and beautiful lanterns, another important part of the Lantern Festival ,or Yuanxiao Festival is eating small dumpling balls made of glutinous rice flour. We call these balls Yuanxiao or Tangyuan. Obviously, they get the name from the festival itself. It is said that the custom of eating Yuanxiao originated during the Eastern Jin Dynasty in the fourth century, then became popular during the Tang and Song periods. The fillings inside the dumplings or Yuansiao are either sweet or salty. Sweet fillings are made of sugar, Walnuts, sesame（芝麻）, osmanthus flowers(桂花), rose petals, sweetened tangerine（橘子）peel, bean paste, or jujube paste（枣子酱）. A single ingredient or any combination can be used as the filling . The salty variety is filled with minced meat（肉末儿）, vegetables or a mixture. The way to make Yuanxiao also varies between northern and southern China. The usual method followed in southern provinces is to shape the dough of rice flour into balls, make a hole, insert the filling, then close the hole and smooth out the dumpling by rolling it between your hands. In North China, sweet or nutmeat stuffing is the usual ingredient. The fillings are pressed into hardened cores, dipped lightly in water and rolled in a flat basket containing dry glutinous rice flour. A layer of the flour sticks to the filling, which is then again dipped in water and rolled a second time in the rice flour. And so it goes, like rolling a snowball, until the dumpling is the desired size. The custom of eating Yuanxiao dumplings remains. This tradition encourages both old and new stores to promote their Yuanxiao products. They all try their best to improve the taste and quality of the dumplings to attract more customers. 1.Which of the following is NOT true? A．The custom of eating Yuanxiao dates back to the fourth century. B．Sugar, rose petals and minced meat are all fillings of Yuanxiao. C．Sweet Yuanxiao are usually made in southern China. D．People in northern China usually make Yuanxiao by rolling like a snowball. 2.Which country does the Lantern Festival come from? A．China B．South Korea C．Jin Dynasty D．Tang and Song periods. 3.Choose the right order of making Tangyuan in southern provinces. ① make a hole and insert the filling ② roll the dough between your hands ③ shape the dough of rice flour into balls ④ close the hole ⑤ prepare some rice flour A．⑤③②①④ B．③⑤①②④ C．③①④②⑤ D．⑤③①④② 4.What is the best title of this passage? A．The Lantern Festival
①化学这门科学在当今世界非常有用。 ②y对于x的依赖关系用y=f(x)来表示。 ③各种物质的导热能力差异很大③各种物质的导热能力差异很大。 ④这个参数可以准确地加以测量。 ⑤半导体的导电率随温度的变化而变化。 ⑥原子能的恰当名称是核能。 ⑦工程材料的性质依赖于（取决于）它们的成分、结构、合成、加工。 ⑧材料科学与工程这个术语将材料科学与材料工程结合在一起，材料科学在材料知识谱的基础知识端，材料工程在应用知识端，两者之间并没有分界线。 ⑨材料的许多性质强烈依赖于其结构，即使材料的成分保持不变。这就是为什么材料中结构-性质关系或者显微结构-性质关系至关重要。 ⑩上面的两个等式极为重要。 The two equations above are of great importance. 十一.金属棒热端的分子随着那里的温度的增加而振动得越来越快。 Molecules at the hot end of a metallic rod vibrate faster as the temperature there increases. 十二.通常这些参数中有一些是已知的。 Usually some of these parameters are known. 十三.当温度低于临界温度时，电子能自由地通过晶格运动。 As temperatures below the critical temperature, the electrons move freely throughout the lattice. 十四. A随温度的这种变化主要是由B的变化引起的。 This variation of A with temperature is due primarily to variations in B. 十五.这种复杂的关系必须用图解来表示。 This complicated relationship must be representedgraphically. 十六.原子间的键合作用部分取决于原子的价电子如何结合在一起。键的类型包括金属键、共价键、离子键、范德华键。 十七.键能与键的强度有关，特别是离子键和共价键结合的材料键能很高。高键能的材料常常具有高的熔点、高的弹性模量和低的热膨胀系数。 ③许多陶瓷材料中发现的离子键是当正电性的原子失去电子给负电性的原子，产生带正电的阳离子和带负电的阴离子而形成的。
计算机专业英语阅读材料 计算机英语（1） Desktop Pattern In the graphical user interface of Microsoft Windows 98,a graphical pattern-called wallpaper-displayed on the desktop (the background "beneath" windows, icons, and dialog boxes). The pattern or picture in the screen background that can be chosen by the user. To change the desktop pattern, choose Display from the Control Panel. 桌面图案 在Microsoft Windows 98的图形用户界面中,一种显示在桌面上称为壁纸(Wallpaper )的图形图案(窗口、图标和对话框后面的背景),屏幕背景可由用户选择图案样式或画面。要改变桌面图案时,从控制面板上选择显示方式。 计算机英语（2） Federated Database In scientific networking ,a collaborative database (part of a collaborator) in which scientists pool their knowledge and discoveries .Federated databases are one proposed solution to the Grand Challenges——problems that are so complex that they far outstrip the capabilities of individual scientists ,or even individual research institutions ,to tackle them independently. 联合式数据库 在科学联网中,科学家们汇集其知识和发现的一种合作数据库(合作的一部分)。联合数据库是对种种重大挑战问题(Grand Challenges)的一种建议性的解决方案——这些问题太复杂,以致于超出单个科学家的能力,甚至单个研究所都无法来单独解决它们。 计算机英语（3） Collapse When creating an outline or viewing a directory tree (such as in the Windows Explorer ),the process of hiding all the outline levels or subdirectories below the selected outline heading or directory. 折叠 当生成一个题纲或观察一个目录树(如在Windows资源管理器中)时,在选定的题纲标题或目录下隐藏所有的题纲层或子目录的过程。 计算机英语（4） Collision In local area networks (LANs) ,a garbled transmission that results when two or more workstations transmit to the same network cable at exactly the same time . Networks have means of preventing collisions. 冲突 在局域网(LANs)中,当两个或多个工作站恰好在同时向同一个网络线路上传送(数据)时产生的错乱传输。网络拥
中考英语阅读理解专项训练 【知识点睛】 一、中考阅读理解命题特点 题型上来看：着重考察学生对整篇文章的把握，侧重考查学生根据语境进行语篇分析和综合利用有效信息解决实际问题的能力 体裁上来看：涉及记叙文、夹叙夹议文、议论文、说明文和应用文；题材内容涉及英语国家文化的多个领域，并逐步增加广告、海报、图画、表格等实用文体 阅读量上看：逐年增加 难度上来看：增加了难度，超过了大纲规定的3%的生词率 二、中考阅读课标要求 义务教育英语课程标准指出：阅读是搜集处理信息、认识世界、发展思维、获得审美体验的重要途径。因此，阅读理解在中考中所占的比例、分值越来越大，主要考查考生通过文字获取信息的能力，阅读速度要求达到每分钟60—80词。选材范围越来越广，除故事、人物轶事外，科普性文章和社会热点话题也多了起来；体裁也趋于多样化，有记叙文、说明文、应用文、议论文等，有时还考查考生理解及解释图表所提供的简单信息的能力；阅读材料丰富多彩，融知识性、趣味性、科学性于一体，既对学生阅读理解能力起着评价作用，又能增长知识、开阔视野。 国家英语课程要求从3年级起开设英语课程，课程标准中的第五级为9年级，也就是初中毕业参加中考时应达到的基本要求。其中对学生“读”的能力做了如下要求： 1. 能根据上下文和构词法推断、理解生词的含义。 2. 能理解段落中各句子之间的逻辑关系。 3. 能找出文章中的主题，理解故事的情节，预测故事情节的发展和可能的结局。 4. 能读懂相应水平的常见体裁的读物。 5. 能根据不同的阅读目的运用简单的阅读策略获取信息。 6. 能利用词典等工具书进行阅读。 7. 课外阅读量应累计达到15万词以上。 三、解题步骤 第一步：读题，把握出题动向 第二步：带着问题速读文章，简单标记题目______________ 第三步：________文中信息，对相关信息进行划线标注 第四步：检查核对 四、阅读题型和做题方法 1、细节理解题 做题方法：利用题目的______________，寻找文中______________，在对应词周围找答案或直接在文中搜索答案，对号入座。它一般是由特殊疑问词what, when, where, how, why, who, which等提问出现，可以直接找到答案。（答案往往不是文中原句） 2、猜测词义题
小学英语阅读理解的常见题型设置及解题技巧 在小学阶段，阅读理解题型灵活多样，但主要有以下题型： 一、读一读，然后选一选。 这种题型的特点是在短文后给出若十个不完整的句子或若干个根据短文内容提出的问题，针对每一题都提供三到四个备选的答案，要求同学们在正确理解短文内容的基础上，从选项中选出一个正确的答案。这类试题的问题一般是紧扣短文内容编排的，既会涉及文章中的细节内容，如文中出现的人物、时间、地点、事件的前因后果等；也会涉及文章中某个词或某个句子的含义以及文章的主旨、大意和标题等。 The big day comes at last! Mrs Jones' third grade students are waiting quietly for her to come into the classroom. Today Amy brings some cakes, Joy brings some napkins, Carlos brings some soda water and Kate brings some cups. Everyone wants the party to he a surprise. Mrs Jones doesn't know the children have known today is her birthday. When she comes into the classroom, the children shout,“Happy birthday, Mrs Jones!”And then the children get a surprise,too. Mrs Jones brings everyone a party hat and an ice cream! 阅读短文，选择最佳答案。 ( ) 1. Mrs Jones' grade students are waiting for her. A. three B.third C.No.3 D.the third ( )2. Carlos brings some _____ ． A. cola B.napkins C.soda water D.cups ( )3．_____ brings some cakes. A. Amy B.Carlos C.Joey D.Kate 分析 题1短文的第二句话告诉我们是琼斯老师的三年级的学生们正静静地等候她的到来。在年级前面应该用序数词来表示，如果是在年级后面就应该用基数词表示。如：the third grade,=Grade Three.同时因为前面有定语Mrs Jones'，所以这里也应该不要the。 题2.3 短文介绍了几个同学分别带了一些东西。卡洛斯带了soda water （汽水），艾米带了蛋糕。 正确答案：1.B 2.C 3. A 二、读一读，然后判断句子正误。 该题型的特点是在短文后给出若干个句子，要求同学们根据短文内容，判断所给的句子意思是否与原文相符。做这类题应该联系短文内容进行发挥，主要是考查对意思相近或相反的几个句子进行鉴别、判断，或是变换词语、句子结构来测试同种意思的不同表达。 There are some public numbers. Do you know when to use these numbers? 110 is a number for calling policeman when you have meet some illegal things. 119 is a number using for a fire accident.