期末试卷综合测试卷（word含答案）
一、初一数学上学期期末试卷解答题压轴题精选（难）
1．如图1，已知∠MON=140°，∠AOC与∠BOC互余，OC平分∠MOB，
（1）在图1中，若∠AOC=40°，则∠BOC=°，∠NOB=°.
（2）在图1中，设∠AOC=α，∠NOB=β，请探究α与β之间的数量关系（必须写出推理的主要过程，但每一步后面不必写出理由）；
（3）在已知条件不变的前提下，当∠AOB绕着点O顺时针转动到如图2的位置，此时α与β之间的数量关系是否还成立？若成立，请说明理由；若不成立，请直接写出此时α与β之间的数量关系.
【答案】（1）解：如图1，
∵∠AOC与∠BOC互余，
∴∠AOC+∠BOC=90°，
∵∠AOC=40°，
∴∠BOC=50°，
∵OC平分∠MOB，
∴∠MOC=∠BOC=50°，
∴∠BOM=100°，
∵∠MON=40°，
∴∠BON=∠MON-∠BOM=140°-100°=40°，
（2）解：β=2α-40°，理由是：
如图1，∵∠AOC=α，
∴∠BOC=90°-α，
∵OC平分∠MOB，
∴∠MOB=2∠BOC=2（90°-α）=180°-2α，
又∵∠MON=∠BOM+∠BON，
∴140°=180°-2α+β，即β=2α-40°；
（3）解：不成立，此时此时α与β之间的数量关系为：2α+β=40°，
理由是：如图2，
∵∠AOC=α，∠NOB=β，
∴∠BOC=90°-α，
∵OC平分∠MOB，
∴∠MOB=2∠BOC=2（90°-α）=180°-2α，
∵∠BOM=∠MON+∠BON，
∴180°-2α=140°+β，即2α+β=40°，
答：不成立，此时此时α与β之间的数量关系为：2α+β=40.
【解析】【分析】（1）先根据余角的定义计算∠BOC=50°，再由角平分线的定义计算∠BOM=100°，根据角的差可得∠BON的度数；（2）同理先计算∠MOB=2∠BOC=2（90°-α）=180°-2α，再根据∠BON=∠MON-∠BOM列等式即可；（3）同理可得∠MOB=180°-2α，再根据∠BON+∠MON=∠BOM列等式即可.
2．已知线段AB=6．
（1）取线段AB的三等分点，这些点连同线段AB的两个端点可以组成多少条线段？求这些线段长度的和；
（2）再在线段AB上取两种点：第一种是线段AB的四等分点；第二种是线段AB的六等分点，这些点连同（1）中的三等分点和线段AB的两个端点可以组成多少条线段？求这些线段长度的和。
【答案】（1）解：如图：点C、D为线段AB的三等分点，
可以组成的线段为：3+2+1=6（条），
∵AB=6，点C、D为线段AB的三等分点，
∴AC=CD=DB=2，AD=BC=4，
∴这些线段长度的和为：2+2+2+4+4+6=20.
（2）解：再在线段AB上取两种点：第一种是线段AB的四等分点D1、D2、D3；第二种是线段AB的六等分点E1、E2，
∴这些点连同（1）中的三等分点和线段AB的两个端点可以组成多少条线段共有1+2+3+…+8=36（条）；
根据题意以A为原点，AB为正方向，建立数轴，则各点对应的数为：
A：0；B：6；C：2；D：4；D1：1.5；D2：3；D3：4.5；E1：1；E2：5；
∴①以A、B为端点的线段有7+7+1=15（条），长度和为：6×8=48；
②不以A、B为端点，以E1、E2为端点的线段有5+5+1=11（条），长度和为：4×6=24；
③不以A、B、E1、E2为端点，以D1、D3为端点的线段有3+3+1=7（条），长度和为：3×4=12；
④不以A、B、E1、E2、D1、D3为端点，以C、D为端点的线段有1+1+1=3（条），长度和为：2×2=4；
∴这些线段长度的和为：48+24+12+4=88.
【解析】【分析】（1）如图，根据线段的三等分点可分别求得每条线段的长度，再由线段的概念先找出所有线段，从而求得它们的和.
（2）再在线段AB上取两种点：第一种是线段AB的四等分点D1、D2、D3；第二种是线段AB的六等分点E1、E2；根据线段定义和数线段的规律求得线段条数；根据题意以A为原点，AB为正方向，建立数轴，则各点对应的数为：A：0；B：6；C：2；D：4；D1：1.5；D2：3；D3：4.5；E1：1；E2：5；再分情况讨论，从而求得所有线段条数和这些线段的长度.
3．已知点O是直线AB上的一点，∠COE=120°，射线OF是∠AOE的一条三等分线，且∠AOF= ∠AOE．（本题所涉及的角指小于平角的角）
（1）如图，当射线OC、OE、OF在直线AB的同侧，∠BOE=15°，求∠COF的度数；
（2）如图，当射线OC、OE、OF在直线AB的同侧，∠FOE比∠BOE的余角大40°，求∠COF的度数；
（3）当射线OE、OF在直线AB上方，射线OC在直线AB下方，∠AOF＜30°，其余条件不变，请同学们自己画出符合题意的图形，探究∠FOC与∠BOE确定的数量关系式，请直接给出你的结论．
【答案】（1）解：∵∠AOE+∠BOE=180°，∠BOE=15°，
∴∠AOE=180°-15°=165°
∴∠AOF= ∠AOE=×165°=55°
∵∠AOC=∠AOE-∠COE=165°-120°=45°
∴∠COF=∠AOF-∠AOC=55°-45°=10°
答：∠COF的度数为10°.
（2）解：设∠BOE=x，则∠BOE的余角为90°-x.
∵∠FOE比∠BOE的余角大40°，
∴∠FOE=130°-x
∵∠COE=120°，则∠COF=x-10°，∠AOC=60°-x，
∴∠AOF=∠AOC+∠COF=50°
∵∠AOF= ∠AOE
∴∠AOE=150°
∴∠BOE=x=180°-150°=30°
∴∠COF=x-10°=30°-10°=20°
答：∠COF的度数为20°
（3）解：∠FOC=∠BOE
如图，
设∠AOF=x
∵∠AOF=∠AOE
∴∠AOE=3x
∴∠EOF=2x，∠BOE=180°-3x=3（60°-x）
∵∠COE=120°
∴∠AOC=120°-3x
∴∠COF=∠AOC+∠AOF=120°-3x+x=2（60°-x）
∴
∴∠FOC=∠BOE
【解析】【分析】（1）利用邻补角的定义及已知求出∠AOE、∠AOF的度数，再利用∠AOC=∠AOE-∠COE，求出∠AOC的度数，然后根据∠COF=∠AOF-∠AOC，可求得结果。（2）设∠BOE=x，利用余角的定义及∠FOE比∠BOE的余角大40°，用含x代数式表示出∠FOE、∠COF、∠AOC，再求出∠AOF的度数，即可得出∠AOE的度数，然后求出x的值，即可得出答案。
（3）根据题意画出图形，设∠AOF=x，利用已知分别用含x代数式表示出∠AOE、∠EOF、∠BOE，再用含x的代数式表示出∠FOC，然后就可得出∠FOC与∠BOE确定的数量关系式。
4．已知直线AB∥CD，直线EF与AB，CD分别相交于点E，F．
（1）如图1，若∠1=60°，求∠2，∠3的度数．
（2）若点P是平面内的一个动点，连结PE，PF，探索∠EPF，∠PEB，∠PFD三个角之间的关系．
①当点P在图（2）的位置时，可得∠EPF=∠PEB+∠PFD请阅读下面的解答过程并填空（理由或数学式）
解：如图2，过点P作MN∥AB
则∠EPM=∠PEB（________）
∵AB∥CD（已知）MN∥AB（作图）
∴MN∥CD（________）
∴∠MPF=∠PFD （________）
∴________=∠PEB+∠PFD（等式的性质）
即：∠EPF=∠PEB+∠PFD
②拓展应用，当点P在图3的位置时，此时∠EPF=80°，∠PEB=156°，则∠PFD=________度．
③当点P在图4的位置时，请直接写出∠EPF，∠PEB，∠PFD三个角之间关系________．【答案】（1）解：∵∠2=∠1，∠1=60°
∴∠2=60°，
∵AB∥CD
∴∠3=∠1=60°
（2）两直线平行，内错角相等；如果两条直线都和第三条直线平行，那么这两条直线也互相平行；两直线平行，内错角相等；∠EPM+∠MPF；124；∠EPF+∠PFD=∠PEB
【解析】【解答】（2）①如图2，过点P作MN∥AB，则∠EPM=∠PEB（两直线平行，内错角相等）
∵AB∥CD（已知），MN∥AB，
∴MN∥CD（如果两条直线都和第三条直线平行，那么这两条直线也互相平行）
∴∠MPF=∠PFD（两直线平行，内错角相等）
∴∠EPM+∠MPF=∠PEB+∠PFD（等式的性质）
即∠EPF=∠PEB+∠PFD；
故答案为：两直线平行，内错角相等；如果两条直线都和第三条直线平行，那么这两条直线也互相平行；两直线平行，内错角相等；∠EPM+∠MPF；
②过点P作PM∥AB，如图3所示：
则∠PEB+∠EPM=180°，∠MPF+∠PFD=180°，
∴∠PEB+∠EPM+∠MPF+∠PFD=180°+180°=360°，
即∠EPF+∠PEB+∠PFD=360°，
∴∠PFD=360°﹣80°﹣156°=124°；
故答案为：124；
③∠EPF+∠PFD=∠PEB．
故答案为：∠EPF+∠PFD=∠PEB．
【分析】（1）利用对顶角相等，可证∠1=∠2，可求出∠2的度数，再根据两直线平行，同位角相等，就可求出∠3的度数。
（2）① 利用两直线平行，内错角相等，可证∠EPM=∠PEB，再根据同平行于一条直线的两直线平行，可证得MN∥CD，然后根据两直线平行，内错角相等，可证得结论；②利用平行线的性质：两直线平行，同旁内角互补，可证∠EPF+∠PEB+∠PFD=360°，代入计算可求出∩PFD的度数；③利用平行线的性质可证∠EPF，∠PEB，∠PFD三个角之间关系。
5．如图，点B、C在线段AD上，CD＝2AB＋3．
（1）若点C是线段AD的中点，求BC－AB的值；
（2）若BC＝AD，求BC－AB的值；
（3）若线段AC上有一点P（不与点B重合），AP＋AC＝DP，求BP的长．
【答案】（1）解：设AB长为x，BC长为y，则CD=2x+3．若C是AB的中点，则AC=CD，即x+y=2x+3，得：y-x=3，即BC-AB=3
（2）解：设AB长为x，BC长为y，若BC= CD，即AB+CD=3BC，∴x+2x+3=3y，∴y=x+1，即y-x=1，∴BC-AB=1
（3）解：以A为原点，AD方向为正方向，1为单位长度建立数轴，则A：0，B：x，C：x+y，D：x+y+2x+3=3x+y+3．设P：p，由已知得：0≤p≤x+y，则AP=p，AC=x+y，DP=3x+y+3-p，∵AP+AC=DP，BP= ，∴p+x+y=3x+y+3-p，解得：2p-2x=3，∴p-x=1.5，∴BP=1.5
【解析】【分析】（1）此题可以设未知数表示题中线段的长度关系，设AB长为x，BC长为y，则AC=AB+BC=x+y,CD=2x+3 ，根据中点的定义得出 AC=CD ，从而列出方程，变形即可得出答案；
（2）设AB长为x，BC长为y ，则CD=2x+3 ，由BC= CD，得出AB+CD=3BC，从而列出方程变形即可得出答案；
（3）设AB长为x，BC长为y ，则CD=2x+3 ，以A为原点，AD方向为正方向，1为单位长度建立数轴，则A点表示的数为0，B点表示的数为x，C点表示的数为x+y，D点表示的数为x+y+2x+3=3x+y+3．设P点表示的数为p，由已知得：0≤p≤x+y，则AP=p，AC=x+y，DP=3x+y+3-p，由AP+AC=DP，列出方程，并行得出P-X的值，再根据BP= 即可得出答案。
6．
（1）感知：如图①，若AB∥CD，点P在A
B、CD内部，则∠P、∠A、∠C满足的数量关系是________．
（2）探究：如图②，若AB∥CD，点P在AB、CD外部，则∠APC、∠A、∠C满足的数量关系是________．
请补全以下证明过程：
证明：如图③，过点P作PQ∥AB
∴∠A＝________
∵AB∥CD，PQ∥AB
∴________∥CD
∴∠C＝∠________
∵∠APC＝∠________﹣∠________
∴∠APC＝________
（3）应用：
① 如图④，为北斗七星的位置图，如图⑤，将北斗七星分别标为A、B、C、D、E、F、
G，其中B、C、D三点在一条直线上，AB∥EF，则∠B、∠D、∠E满足的数量关系是________．
② 如图⑥，在（1）问的条件下，延长AB到点M，延长FE到点N，过点B和点E分别作射线BP和EP，交于点P，使得BD平分∠MBP，EN平分∠DEP，若∠MBD＝25°，则∠D﹣∠P＝________°．
【答案】（1）∠P＝∠A+∠C
（2）∠APC＝∠A﹣∠C；∠APQ；PQ；∠CPQ；∠APQ；∠CPQ；∠A﹣∠C
（3）解：∠D+∠B﹣∠E＝180°；75
（1）∠P＝∠A+∠C；∠APC＝∠A﹣∠C，∠APQ，PQ，∠CPQ，∠APQ，∠CPQ，∠A﹣∠C；∠D+∠B﹣∠E＝180°（2）75
【解析】【解答】解：（1）如图①，过点P作PQ∥AB
∴∠A＝∠APQ，
∵AB∥CD，PQ∥AB
∴PQ∥CD，
∴∠C＝∠QPC，
∴∠APQ+∠QPC＝∠A+∠C，
∠APC＝∠A+∠C．
故答案为∠P＝∠A+∠C；（2）如图③，过点P作PQ∥AB
∴∠A＝∠APQ
∵AB∥CD，PQ∥AB
∴PQ∥CD
∴∠C＝∠CPQ
∵∠APC＝∠APQ﹣∠CPQ
∴∠APC＝∠A﹣∠C．
故答案为：∠APC＝∠A﹣∠C，∠APQ，PQ，∠CPQ，∠APQ，∠CPQ，∠A﹣∠C．（3）①如图⑤，过点D作DH∥EF，
∴∠HDE＝∠E，
∵AB∥EF，DH∥EF
∴AB∥DH，
∴∠B+∠BDH＝180°，
即∠BDH＝180°﹣∠B，
∴∠HDE+∠BDH＝∠E+180°﹣∠B，
即∠BDE+∠B﹣∠E＝180°，
故答案为∠D+∠B﹣∠E＝180°，
②如图⑥，过点P作PH∥EF，
∴∠EPH＝∠NEP，
∵AB∥EF，PH∥EF，
∴AB∥PH，
∴∠MBP+∠BPH＝180°，
∵BD平分∠MBP，∠MBD＝25°，
∠MBP＝2∠MBD＝2×25°＝50°，
∠BPH＝180°﹣50°＝130°，
∵EN平分∠DEP，
∴∠NEP＝∠DEN
∴∠BPE＝∠BPH﹣∠EPH＝∠BPH﹣∠NEP＝∠BPH﹣∠DEN＝130°﹣（180°﹣∠DEF）＝∠DEF﹣50°
由①∠D+∠ABD﹣∠DEF＝180°，
∵∠MBD＝25°，
∴∠ABD＝155°，
∴∠D+∠155°﹣∠DEF＝180°，
∴∠DEF＝∠D﹣25°
∴∠BPE＝∠DEF﹣50°＝∠D﹣25°﹣50°＝∠D﹣75°
∠D﹣∠BPE＝75°
即∠D﹣∠P＝75°，
故答案75．
【分析】作平行线利用平行线的性质与角平分线的性质通过角等量关系转化解题即可．7．如图，C为线段AB上一点，点D为BC的中点，且AB＝18cm，AC＝4CD．
（1）图中共有________条线段；
（2）求AC的长；
（3）若点E在直线AB上，且EA＝2cm，求BE的长．
【答案】（1）解：图中有四个点，线段有．
故答案为：6；
（2）解：由点D为BC的中点，得
BC＝2CD＝2BD，
由线段的和差，得
AB＝AC+BC，即4CD+2CD＝18，
解得CD＝3，
AC＝4CD＝4×3＝12cm
（3）解：①当点E在线段AB上时，由线段的和差，得
BE＝AB﹣AE＝18﹣2＝16cm，
②当点E在线段BA的延长线上，由线段的和差，得
BE＝AB+AE＝18+2＝20cm．
综上所述：BE的长为16cm或20cm．
【解析】【分析】（1）线段的个数为，n为点的个数.（2）由题意易推出CD的长度，再算出AC＝4CD即可.（3）E点可在A点的两边讨论即可.
8．已知∠AOB和∠AOC是同一个平面内的两个角,OD是∠BOC的平分线.
（1）若∠AOB=50°,∠AOC=70°,如图(1),图(2),求∠AOD的度数；
（2）若∠AOB= 度,∠AOC= 度,其中且
求∠AOD的度数(结果用含的代数式表示)，请画出图形，直接写出答案。
【答案】（1）解：图1中∠BOC=∠AOC﹣∠AOB=70°﹣50°=20°，
∵OD是∠BOC的平分线，
∴∠BOD= ∠BOC=10°，
∴∠AOD=∠AOB+∠BOD=50°+10°=60°；
图2中∠BOC=∠AOC+∠AOB=120°，
∵OD是∠BOC的平分线，
∴∠BOD= ∠BOC=60°，
∴∠AOD=∠BOD﹣∠AOB=60°﹣50°=10°；
（2）解：根据题意可知∠AOB= 度，∠AOC= 度，其中
且，
如图1中，
∠BOC=∠AOC﹣∠AOB=n﹣m，
∵OD是∠BOC的平分线，
∴∠BOD= ∠BOC= ，
∴∠AOD=∠AOB+∠BOD= ；
如图2中，
∠BOC=∠AOC+∠AOB=m+n，
∵OD是∠BOC的平分线，
∴∠BOD= ∠BOC= ，
∴∠AOD=∠BOD﹣∠AOB= .
【解析】【分析】（1）图1中∠BOC=∠AOC﹣∠AOB=20°，则∠BOD=10°，根据∠AOD=∠AOB+∠BOD即得解；图2中∠BOC=∠AOC+∠AOB=120°，则∠BOD=60°，根据∠AOD=∠BOD﹣∠AOB即可得解；（2）图1中∠BOC=∠AOC﹣∠AOB=n﹣m，则∠BOD=
，故∠AOD=∠AOB+∠BOD= ；图2中∠BOC=∠AOC+∠AOB=m+n，则∠BOD= ，故∠AOD=∠BOD﹣∠AOB= .
9．已知将一副三角板(直角三角板OAB和直角三角板OCD∠AOB=90°，∠ABO=45°，∠CDO=90°，∠COD=60°)
（1）如图1摆放，点O，A，C在一直线上，则∠BOD的度数是多少?
（2）如图2，将直角三角板OCD绕点O逆时针方向转动，若要OB恰好平分∠COD，则∠AOC的度数是多少?
（3）如图3，当三角板OCD摆放在∠AOB内部时，作射线OM平分∠AOC，射线ON平分∠BOD，如果三角板OCD在∠AOB内绕点Q任意转动，∠M0N的度数是否发生变化?如果不变，求其值；如果变化，说明理由。
【答案】（1）解：∠BOD=∠AOB?∠COD=90 ?60 =30
（2）解：∵OB平分∠COD,
∴∠BOC= ∠COD= ×60 =30 ，
∴∠AOC=∠A OB?∠BOC=90 ?30 =60
（3）解：∠BOD+∠AOC=90°?∠COD=90 ?60 =30 ，
(∠BOD+∠AOC)= ×30 =15 ，
∠MON= (∠BOD+∠AOC)+∠COD=15°+60 =75 .
即∠MON的度数不会发生变化，总是75 ．
【解析】【分析】（1）根据余角的性质和含义即可得到答案；
（2）根据角平分线的性质计算得到∠BOC的度数为30°，由余角的性质即可得到答案；
（3）由角平分线的性质即可得到∠BOD和∠AOC的度数和的，由角的和差关系进行计算得到答案即可。
10．已知点O在直线MN上，过点O作射线OP，使∠MOP=130°，将一块直角三角板的直
角顶点始终放在点O处．
（1）如图①，当三角板的一边OA在射线OM上，另一边OB在直线MN的上方时，求∠POB的度数；
（2）若将三角板绕点O旋转至图②所示的位置，此时OB恰好平分∠PON，求∠BOP和∠AOM 的度数；
（3）若将三角板绕点O旋转至图③所示位置，此时OA在∠PON 的内部，若OP所在的直线平分∠MOB，求∠POA 的度数；
【答案】（1）解：∠POB=∠MOP-∠AOB=130°-90°=40°．
（2）解：∵∠MON是平角，∠MOP=130°，
∴∠PON=∠MON-∠MOP=180°-130°=50°
∵OB 平分∠PON，
∴∠BOP= ∠PON=25°
∵∠AOB=90゜，
∴∠AOP=∠AOB-∠BOP=90°-25°=65°
∴∠MOA=∠MOP-∠AOP=130°-65°=65°；
（3）解：如图，OE是PO的延长线，
∵∠MOP=130°
∴∠MOE=50°
∵OE是∠MOB的平分线，
∴∠MOB=100°，
∴∠BON=80°
∵∠AOB=90°
∴∠AON=∠AOB-∠BON=90°-80°=10°
∴∠POA=∠PON-∠AON=50°-10°=40°
【解析】【分析】（1）根据题意，∠POB=∠POA-∠AOB代入数据即可求出结论；（2）根
据题意，∠PON=180°-∠POM,又根据角平分线的定义可得∠POB=∠NOB= ,代入已知即可求解；再根据余角定义求出∠POA的度数；（3）从已知条件可得，∠MOE=180°-
∠MOP,再根据角平分线的定义得∠MOB=2∠MOE, ∠NOA=180°-∠MOB, ∠AON=90°-∠BON, ∠POB=∠PON-∠AON,代入求值即可．
11．如图
（1）如图1，AB∥CD，∠AEP=40°，∠PFD=130°。求∠EPF的度数。
小明想到了以下方法(不完整)，请填写以下结论的依据：
如图1，过点P作PM∥AB，
∴∠1=∠AEP=40°(________)
∵AB∥CD，(已知)
∴PM∥CD，(________)
∠2+∠PFD=180°(________)
∵∠PFD=130°，∴∠2=180°-130°=50°
∴∠1+∠2=40°+50°=90°
即∠EPF=90°
（2）如图2，AB∥CD，点P在AB，CD外，问∠PEA，∠PFC，∠P之间有何数量关系?请说明理由；
（3）如图3所示，在(2)的条件下，已知∠P=α，∠PEA的平分线和ZPFC的平分线交于点G，用含有α的式子表示∠G的度数是________。(直接写出答案，不需要写出过程)
【答案】（1）两直线平行，内错角相等；平行于同一条直线的两条直线互相平行；两直线平行，同旁内角互补
（2）解：
理由如下：过点作，则
∴
∵
∴
∵
∴
∴
即 .
（3）
【解析】【解答】（3）如图：
∵EG平分∠PEA，FG平分∠PFC，
∴∠1=∠PFC，∠2=∠PEA，
∴∠1-∠2=∠PFC-∠PEA=（∠PFC-∠PEA），
∵∠PFC=∠PEA+∠P，
∴∠PFC-∠PEA=∠P，
∴∠1-∠2=∠P，
∵∠3=∠P+∠2，
∴∠G=∠3-∠1=∠P+∠2-∠1=∠P=α.
【分析】（1）根据平行线的性质及平行公理，即可求解；
（2）过点P作PN∥AB，根据平行公理得PN∥CD，得出∠PFC=∠FPN，由AB∥CD得出∠PEA=∠NPE，
从而得出∠FPN=∠PEA+∠FPE，即可求出∠PFC=∠PEA+∠FPE，即可求解；
（3）根据角平分线的定义得出∠1=∠PFC，∠2=-∠PEA，由∠PFC=∠PEA+∠P，得出∠1-∠2=
∠P，由三角形的外角性质得出∠G=∠3-∠1，∠3=∠P+∠2，从而求出∠G=α.
12．根据下图回答问题：
（1）如图1，CM平分∠ACD，AM平分∠BAC，∠MAC+∠ACM=90°，请判断AB与CD的位置关系并说明理由；
（2）如图2，当∠M=90°且AB与CD的位置关系保持（1）中的不变，当直角顶点M移动时，问∠BAM与∠MCD是否存在确定的数量关系？并说明理由；
（3）如图3，G为线段AC上一定点，点H为直线CD上一动点且AB与CD的位置关系保持（1）中的不变，当点H在射线CD上运动时（点C除外）∠CGH+∠CHG与∠BAC有何数量关系？猜想结论并说明理由．
【答案】（1）∵CM平分∠ACD，AM平分∠BAC，
∴∠BAC=2∠MAC，∠ACD=2∠ACM，
∵∠MAC+∠ACM=90°，
∴∠BAC+∠ACD=180°，
∴AB∥CD；
（2）∠BAM+∠MCD=90°，
理由：如图，过M作MF∥AB，
∵AB∥CD，
∴MF∥AB∥CD，
∴∠BAM=∠AMF，∠FMC=∠DCM，
∵∠M=90°，
∴∠BAM+∠MCD=90°；
（3）∠BAC=∠CHG+∠CGH．
理由：过点G作GP∥AB，
∵AB∥CD
∴GP∥CD，
∴∠BAC=∠PGC，∠CHG=∠PGH，
∴∠PGC=∠CHG+∠CGH，
∴∠BAC=∠CHG+∠CGH．
【解析】【分析】（1）已知CM平分∠ACD，AM平分∠BAC，根据角平分线的定义可得∠BAC=2∠MAC，∠ACD=2∠ACM，再由∠MAC+∠ACM=90°，即可得∠BAC+∠ACD=180°，根据同旁内角互补，两直线平行即可得AB∥CD；（2）∠BAM+∠MCD=90°，过M作MF∥AB，即可得MF∥AB∥CD，根据平行线的性质可得∠BAM=∠AMF，∠FMC=∠DCM，再由∠M=90°，即可得∠BAM+∠MCD=90°；（3）∠BAC=∠CHG+∠CGH，过点G作GP∥AB，即可得GP∥CD，根据平行线的性质可得∠BAC=∠PGC，∠CHG=∠PGH，所以PGC=∠CHG+∠CGH，即可得∠BAC=∠CHG+∠CGH．
13．已知，与两角的角平分线交于点P，D是射线上一个动点，过点D的直线分别交射线，，于点E，F，C.
（1）如图1，若，，，求的度数；
（2）如图2，若，请探索与的数量关系，并证明你的结论；
（3）在点运动的过程中，请直接写出，与这三个角之间满足的数量关系：________.
【答案】（1）解：∵PA、PB是∠BAM、∠ABN的角平分线，
∴∠BAP=∠PAE= ∠BAM= ，
∠ABP=∠PBE= ∠ABN= ，
∴∠BPC=∠BAP+∠ABP= ；
（2）解：，理由如下：
∵PA、PB是∠BAM、∠ABN的角平分线，
∴设，，
∵，
∴，
∵，
∴，
又∵，
∴，
∴；
（3）
【解析】【解答】解：（3）∵PA、PB是∠BAM、∠ABN的角平分线，
∴设，，
∵，
∴，
如图，当点P在线段BD上时，
，
∴；
如图，当点P在线段BD的延长线上时，
，即，
∴，
即；
故答案为：.
【分析】（1）根据角平分线的性质结合三角形外角的性质即可求解；
（2）设，，根据角平分线的性质结合四边形内角和定理即可求解；
（3）分点P在线段BD上和点P在线段BD的延长线上两种情况讨论即可求解.
14．如图，已知CD∥EF，A，B分别是CD和EF上一点，BC平分∠ABE，BD平分∠ABF
（1）证明：BD⊥BC;
（2）如图，若G是BF上一点，且∠BAG=50°，作∠DAG的平分线交BD于点P，求∠APD 的度数：
（3）如图，过A作AN⊥EF于点N，作AQ∥BC交EF于Q，AP平分∠BAN交EF于P，直接写出∠PAQ=________.
【答案】（1）证明：∵BC平分∠ABE，BD平分∠ABF
∴∠ABC= ∠ABE，∠ABD= ∠ABF
∴∠ABC+∠ABD= （∠ABE+∠ABF）= ×180°=90°
∴BD⊥BC
（2）解：∵CD∥EF
BD平分∠ABF
∴∠ADP=∠DBF= ∠ABF，∠DAB+∠ABF=180°
又AP平分∠DAG，∠BAG=50°
∴∠DAP= ∠DAG
∴∠APD=180°－∠DAP－∠ADP
=180°－∠DAG－∠ABF
=180°－ (∠DAB－∠BAG)－∠ABF
=180°－∠DAB+ ×50°－∠ABF
=180°－ (∠DAB+∠ABF)+25°
=180°－ ×180°+25°
=115°
（3）45°
【解析】【解答】（3）解：如图，
∵AQ∥BC
∴∠1=∠4，∠2+∠3+∠4=180°，
∵BC平分∠ABE，
∴∠1=∠2=∠4，
∴∠3+∠4=90°，
又∵CD∥EF，AN⊥EF，AP平分∠BAN
∴∠PAN= （90°-∠3），∠NAQ=90°-∠4，
∴∠PAQ=∠PAN+∠NAQ= （90°-∠3）+（90°-∠4）
=45°- ∠3+90°-∠4
=135°-（∠3+∠4）
=135°-90°
=45°.
【分析】（1）根据角平分线和平角的定义可得∠CBD=90°，即可得出结论；（2）根据平行线的性质以及角平分线的定义可得∠ADP=∠DBF= ∠ABF，∠DAB+∠ABF=180°，∠DAP= ∠DAG，然后根据出三角形内角和即可求出∠APD的度数；（3）根据平行线的性质以及角平分线的定义可得∠1=∠2=∠4，∠2+∠3+∠4=180°，即∠3+∠4=90°，根据垂直和平行线的性质以及角平分线的定义可得∠PAN= （90°-∠3），∠NAQ=90°-∠4，则∠PAQ=∠PAN+∠NAQ= （90°-∠3）+（90°-∠4），代入计算即可求解.
Part I Multiple Choice(15%) Directions:There are 15 incomplete statements in this part. For each statement there are four choices marked A, B, C and D. Choose the best ONE to complete the statement. (1’x 15=15’) 1. According to the rules of writing a title, “__________” is correct. A. The Way To Improve Our English-Speaking Ability B. My View on the Negative Effects of Ads C. the Myth of a Negro Literature D. the war of Independence 2. Which of the following sentences has punctuation error? A. The alarm clock sounded, the students got up quickly. B. The alarm clock sounded; the students got up quick. C. The alarm clock sounded. The students got up quickly. D. When the alarm clock sounded, the students got up quickly. 3. __________ does not contain in the principles of “choice of words”. A. Accuracy B. Arbitrariness C. Appropriateness D. Conciseness 4. What kind of figures of speech(修辞格)is used in the sentence “This elephant is like a snake as anybody can see.”? A. Metaphor B. Personification C. Simile D. Hyperbole 5. During the TV interview, the singer announced that he was going to _____his new album soon. A.release B. renew C. relieve D. rehearse 6. Greatly agitated, I rushed to the apartment and tried the door, __________ to find it locked. A. only B. just C. hence D. thus 7. As I’ll be away for at least a year, I’d appreciate __________ from you now and then telling me how everyone is getting along. A. hearing B. to hear C. to be hearing D. having heard 8. An introductory paragraph should arouse the reader’s interest and __________ the main idea of the essay. A. ignore B. introduce C. develop D. emphasize 9. Which of the following sentences contains a dangling modifier? A. Coming up the hall, I heard the clock struck 10. B. While Wendy was driving on Greenwood Avenue yesterday afternoon, a tree began to fall toward her car. C. When I was ten, my grandfather died. D. None of the above. 10. Which one is not used as a transition word to give examples?
商务英语写作（2）（B卷） 考试有关事项说明 考试日期：年月日（星期） 答题时间：120分钟。 考试地点： 考试形式：闭卷 Ⅰ. Fill in the blanks. (15%, 1 point for each blank) (1) Technical writing is a form of , a type of , an interactive that involves writers and readers who response to one another. (2) Some reports might present the to solve a business problem; other reports might record that will be useful to assist in future decision making. Either way, is being “reported” that will be useful in making decisions. (3) Doing a business, it usually includes and replies, , orders and their fulfillment, terms of payment, and , etc. (4) A business report conveys information to assist in . It may be long or short, , public or private, or reported on special occasions. (5) Technical writing has many forms, including letters, , reports, , presentations, and . Ⅱ. Multiple choices (15%, 1.5 point for each one)
2012----2013学年度第二学期期末教学质量检测 四年级英语试卷明德 I.选出不同类的单词。（每题2分，共10分）（）1.A January B. rain C. Snow （）2.A short B.tall C. breakfast （）3.A. white B. blue C. favourite （）4.A.Math B.English C. year （）5. A.two B.eleven C. eighth II.把单词与对应的汉语意思连线。（20分） colour 房子schoolbag 有趣的house 尺子February 二月 wind 四月birthday 语文 April 风Chinese 书包 ruler 颜色interesting 生日 III．选择填空。（20分） （）1.These are _____.
A. pens B. ruler C. chair （）2. She ____ on the playground. A. am B. is C. are （）3. My birthday is ___ June. A. in B. at C. on （）4.____ is the first day of the week. A. Monday B. Sunday C. Saturday （）5. I go to school ____ eight o’clock. A. In B. on C. at （）6. ____ name is Kim. A. She B. His C. Her （）7. _____ floor do you live on? A. What B.Where C. Which （）8. ____ you like math? A. Does B. Are C. Do （）9. This is ____ apartment. A. a B. an C. the （）10. I am 1.3 ____ tall. A. metres B. metre C. metres’ （）1. 丹尼在课桌和椅子中间。A.I go to school at eight o’clock.
写作基础训练 Ⅰ) 五大句型 根据谓语动词的不同性质，语言学家总结出英语的五大基本句型。无论多么错综复杂的句子，都是在五大句型的基础上扩展而成的。总体上，句子必须包含至少一个主谓结构。有了这种认识，就可以避免写出残缺句。 使用动词时应考虑以下几个方面： ●及物还是不及物？ ●短暂性还是持续性？ ●描述动作还是状态？ ●一次性动作还是习惯性动作？ ●助动词还是习动词。 1.主+谓(+状) SV(A) The sun rises in the east. Everything is going on well. We set off in the early morning. 2.主+系+表SVC He is an expert in computers. They remain silent. Leaves turn yellow in autumn. 3.主+谓+宾SVO I like sports. Mary has finished her work. My father will meet one of my uncles at the airport. 4.主+谓+双宾SV oO Pass me the salt, please. (= pass the salt to me, please.) Would you buy him a gift? (= would you buy a gift for him?) The teacher asked me a question. (= the teacher asked a question of me.) 5.主+谓+宾+宾补SVOC The young couple watched their baby play on the grassland. Carl Marx made London the base for his revolutionary work. I found it hard to keep up with them. Exercise1. SV A 1.他期盼的那封信最终来了。 2.生活费用上涨了百分之二十。 3.那座寺庙坐落在山顶上。 4.谢谢你，我自己应付得了。 5.作为艺术家，他的成功开始了。 6.时不我待。 7.鸟可以随时飞翔。 8.听了他的话，在场的人都笑了。 9.他们停下来休息， 10.车子突然抛锚了。 Exercise2. SVC 11.天气变得越来越暖和了。 12.他的梦想会成真吗？ 13.船到桥头自然直。 14.这个主意听起来很有道理。 15.做一名知名作家让人感觉不错。 16.我感到有些紧张。 17.女士们希望永葆青春。 18.孩子们很容易地入睡了。 19.腐败的食物对健康不利。 20.你妹妹看上去病了。 Exercise3. SVO 21.你打算到哪儿去度假？ 22.我对这件事全然不知。 23.失败后他从不泄气。 24.你最后一次见到它是什么时候？ 25.你应当为他人树立榜样。 26.晚会上我们玩得很开心。 27.教室需要打扫。 28.结果令我失望。 29.有钱人应帮助穷人。 30.妇女可以把任何事做得与男人一样好。Exercise4. SV oO 31.他送给我一本书作为生日礼物。 32.我可以把我的朋友介绍给你的父母吗？ 33.老师耐心地向我们解释了原因。 34.你给我买了什么东西没有？ 35.她为全家人做一日三餐。 36.小时候爸爸经常给我讲故事。 37.借给我五元钱，好吗？ 38.我侄子每两个月给我写封信 39.经理已经为客人订了房间。 40.我可以请你帮忙吗？ Exercise5. SVOC 41.同学们选他当班长。
英语写作试题（一） I. Supply the missing paragraph (20 points) The following passage is incomplete with one body paragraph missing. Study the passage carefully and write the missing paragraph in about 100 words. Make sure that your tone and diction are in unity with the passage provided. Attaining Success in College Succeeding in college is not only important to getting and education, but also crucial in this day and age to success in the work place. To me, the three most important things for attaining a successful college experience are having smart classroom conduct, taking advantage of campus resources, and making college the first priority. _______________________________________________________________________________ _______________________________________________________________________________ _______________________________________________________________________________ _______________________________________________________________________________ _______________________________________________________________________________ ______________________________________________________________________________ Making good use of campus resources is also of great importance to college success. The school library has many resources for the growth of the students’ mind. With computers and copy-machines for individual use, computer labs and writing labs are there not just for learning purposes but also for actual help with writing papers. The “office hours” will help the students build a close relationship with their professors and give them access to the professors’ mind. From the professors the students can acquire possible extra information that may put them ahead of their study. All these resources are free, since they are funded by student tuitions. So taking good advantage of the resources can only make the students’ education more attainable. Finally, any students who want to assure success must establish school as the top priority. Personally I have watched some students slowly loosen up; I have seen a pattern of partying and a lack of motivation. Many of the freshmen have no idea why they are in college, and their “eyes” often tell it all. This world is so rich in distractions that it is hard to keep a strong focus, especially if one is just starting his or her academic career. It is said that the first semester is often the most “unsuccessful” one. This certainly rings true for me. I made mistakes in this regard and eventually learned that, to achieve success, school must always be placed above other things. In my college experience, I have observed and learned how to achieve success. I wish someone had told me earlier the importance of having that smart classroom conduct, of fully utilizing the school resources, and of making college my top priority. Then, my college beginnings would not have been so rocky and tough. II. Write an outline (20 points) Read the following passage carefully and compose a “topic outline” for it. Smell Smell, as a means of nonverbal communication, is important. Odor communicates not only when we are face to face with another person, but also when the other personis not present. People from different cultures may have different attitudes toward body odors. Most people in the West respond negatively to what they consider bad odors such as body odor, breath odor, or
商务英语写作试卷 （课程代码：5440） I. Multiple-choice: For each sentence there are four choices marked A, B, C, and D. Choose the one that best completes the sentence. (1 point each) 1.Please let us know which of our products _______. A. you are interested B. are you interested C. they are interested D. you are interested in 2.We ______ your name and address _______ the Chinese Embassy in Bonn. A. are learning….from B. have learned ….from C. have come to know….of D. have been given ….from 3.We are now enclosing a pricelist for all the items you _______ in your letter under reply. A. required B. inquired about C. said D. informed 4.If you are prepared to increase your ______ to 15%, we shall be pleased to purchase the complete stock. A. price B. discount C. sales volume D. cost 5. A recent market survey reveals that such articles are no longer __________. A. in demand B. demanded C. on demand D. for demand 6.This is a new product but it is gaining _______ popularity in the world market. A. many more B. better and better C. increasingly steady D. steadily increasing 7.Concerning the ________ L/C, we wish to inform you that there are several clauses that need amendment. A. subjective B. caption C. subjected D. captioned 8.We wish to make it clear to you that we shall not ______ the shipment if they arrive after December 19, 2005. A. arrange B. receive C. accept D. acknowledge 9.Following your order ______ 400 pieces of electronic toys last year, we are pleased to receive your order No. 456 _______ the same quantity. A. for, of B. of , of C. for, for D. with, for 10.As agreed upon in our negotiation, payment _______ L/C. A. by B. will C. are by D. is to be made by 11.We will do our best to _______ shipment to meet your requirements in time. A. comply B. make C. expediting D. arranged 12.Any loss or damage noticed when the goods are delivered must be reported to the ______ at the time, otherwise he will not be responsible for it. A. consignor B. consignee C. shipper D. carrier 13.For all the remaining items the stated dates of delivery are approximate, but _______ would these dates be exceeded by more that ten days. A. in no case B. in any case C. by all means D. under any circumstances 14.Your failure to open the L/C in time will ________impossible for us to deliver goods within the period stipulated in the contract. A. make them be B. make it be C. make it D. make that be 15.The stipulations in your L/C _________ not in accordance with the contract, we have to request you to make an amendment. A. is B. being C. is to be D. would be 16.In _______ of quality, our make is superior. A. terms B. term C. connection D. connections 17.__________, the buyers have urged us to expedite shipment of their order. A. The season approaching B. The season is approaching C. As season approaching D. The season was approaching 18.We accept as an exception your order _________ business with you.
英语基本句型写作练习一 分析下列句子成分并写出句型。 1. You should study hard. 2. She went home very late yesterday evening. 3. That morning we talked a great deal. 4. I wrote a letter last night. 5. I want to talk with you this afternoon. 6. He has read this book many times. 7. My brothers are all college students. 8. Mrs Brown looks very healthy. 9. Mr Johnson taught us German last year. 10. In winter, the days are short and the nights are long. 11. Grandma told me an interesting story last night. 12. Mary handed the wallet to the schoolmaster. 13. Would you please pass me the dictionary? 14. We call her Alice. 15. His parents named him John. 16. All of us considered him honest. 17．They pushed the door open.
18. There isn’t going to be a meeting tonight. 19. There was only a well in the village. 20. There is (are) a teacher of music and a teacher of art in the school.指出下列句子加粗部分是什么句子成分： 1. The students got on the school bus. 2. He handed me the newspaper. 3. I shall answer your question after class. 4. What a beautiful Chinese painting! 5. They went hunting together early in the morning. 6. His job is to train swimmers. 7. He took many photos of the palaces in Beijing. 8. There is going to be an American film tonight. 9. He is to leave for Shanghai tomorrow. 10. His wish is to become a scientist. 11. The meeting will last two hours. 12. They have carried out the plan successfully. 13. At the age of fifteen he became a famous pianist. 14. He showed the ticket to the conductor. 15．They have set the thief free.
大学商务英语写作考试 复习题 https://www.doczj.com/doc/df13262136.html,work Information Technology Company.2020YEAR
商务英语复习题 1.What information should be contained in the first information section of a resume? A.the job objective B.family history and gender identification C.the date D.contect information 2.Which of the following is a “6C” A.Colorfulness B.Concreteness https://www.doczj.com/doc/df13262136.html,fortability https://www.doczj.com/doc/df13262136.html,patibility 3.What is the first thing to appear on a bussiness letter A.the date B.the letterhead C.the inside address D.the attention line 4.When writing the date on a business letter you should take care to do what? A.make sure you always put the year first before the month and day B.always use only numbers in the date field C.make sure you always put the month first before the date and year D.spell out the month 5.How many spaces are needed between the complimentary close of a letter and the typed name of the person writing the letter? A.3 B.2 C.4 D. as many as needed 6.What should you do if you are worried that the reader of a request you are asking will not honor your request? A.write the letter in an indirect style B.write the letter in a direct style C.ask them to please grant your request D.be forceful and demand they honor your request
六年级下册英语期末测试试题 一、听句子选出句中所包含的单词：5分 ( )1.A.wash B.washed C.washing D.washed ( )2. A. happy B.excited C.tired D.angry ( )3.A.tall B.taller C.short D.shorter ( )4. A.go B.went C.want D.goes ( )5.A.big B.biger C.bigger D.strong 二、听问句选答语： ( ) 1. A.I’m fine. B.I’m nine. C.I’m 50kg. ( ) 2. A.The elephant. B. The cat. ( ) 3. A.I’m angry B.I have a headache. C. I feel sick. ( ) 4. A.Yes, I do. B.Yes, I did. C.No,I did. ( ) 5. A.It’s black. B.It’s a clock. C.It’s four o’clock. 三、听短文判断正误：10分 ( ) 1. Jenny’s family was very busy last weekend. ( ) 2. Jenny cleaned the floor yesterday. ( ) 3. Bob washed his clothes. ( ) 4. Father cooked supper. ( ) 5. Mother read a newspaper. 四．听短文补全对话：10分 Today was a fun day. I______my_________, then I _____to Amy’s home in the morning. we ______a story book, then we ______to
一．判断题：（对的打√，错的打×，每题1分，共10分） 1．批复是主动行文。（） 2．因时间紧迫，可在同一份请示中向上级机关请求拨款建办公楼和买汽车。（） 3．某市教育局向市财政局申请普九教育经费，用请示行文。（）4．桂洲市人民政府办公室2002年第5号文的发文字号为桂市办〔2002〕第5号。（） 5．2001年1月1日起施行的《国家行政机关公文处理办法》是我国目前关于行政公文处理的一份最具权威的文件。（） 6．宁波市海曙区白云街道宣布新当选的领导班子成员名单，用通报行文。（） 7．总结和计划的写作目的都是为了指导未来实践。（）8．联合行文的发文字号应该并排写在一起。（） 9．机关单位对社会的某一现象、某一事件或对本单位的内部事件、问题进行调查研究后写出的书面报告，可称为调查报告。（） ！ 10．会议纪要就是对会议全程的如实纪录。（） 二．单项选择题：（每题2分，共30分） 1．为及时简要地汇报工作情况，反映情况和交流信息，各级行政机关、企事业单位、社会团体经常定期 或不定期编发（）。 A．通报B．通知C．意见D．简报 2．浙江省人民政府向所属县、市人民政府下发《财政部关于严格控制各级行政机关、事业单位发放奖金 的紧急通知》，用（）行文。 A、指示通知 B、批转通知 C、转发通知 D、知照通知3．商贸学院学生李茗救了一个落水儿童，学校决定发文进行表彰，于是发了一篇（） ￥ A.通告 B.通报 C.通知 D.决定 4. 下列关于“批复”文种的论述，正确的是（） A．平行文B．指挥下级机关布置工作，提出工作原则和要求 C．答复同级机关询问事项D．态度要鲜明，措辞要明确 5. 发文字号的位置应在（）。 A．版尾、抄送机关与印发机关之间，居中。 B．主体、标题与主送机关之间，居中。 C．眉首，红色隔离线以上，发文机关标识以下，居中。 D．眉首，红色隔离线以上右侧。 6.公文的制发者是____。 A．合法存在的机关和组织B．个人C．单位领导人D．公民
机密★启用前 大连理工大学网络教育学院 大工20春《商务英语写作-精品课程》课程考试 期末考试复习题 ☆注意事项：本复习题满分共：400分 一、单项选择题（本大题共30小题，每小题2分，共60分） 1.Please let us know which of our products _______. A. you are interested B. are you interested C. they are interested D. you are interested in 2.We ______ your name and address _______ the Chinese Embassy in Bonn. A. are learning….from B. have learned ….from C. have come to know….of D. have been given ….from 3.We are now enclosing a price list for all the items you _______ in your letter under reply. A. required B. inquired about C. said D. informed 4.If you are prepared to increase your ______ to 15%, we shall be pleased to purchase the complete stock. A. price B. discount C. sales volume D. cost 5. A recent market survey reveals that such articles are no longer __________. A. in demand B. demanded C. on demand D. for demand 6. We will do our best to _______ shipment to meet your requirements in time. A. comply B. make C. expediting D. arranged 7. Any loss or damage noticed when the goods are delivered must be reported to the ______ at the time, otherwise he will not be responsible for it. A. consignor B. consignee C. shipper D. carrier 8. For all the remaining items the stated dates of delivery are approximate, but _______ would these dates be exceeded by more that ten days. A. in no case B. in any case C. by all means D. under any circumstances 9. Your failure to open the L/C in time will ________impossible for us to deliver goods within the
新概念英语第一册（1-144课）期末测试试卷 (1) 数词, 冠词, 介词, 动词时态变化, 比较级和最高级 一写出复数 1. radio 2. knife 3. glass 4. shelf 5. boss 6. dress 7. housewife 9. leaf 10. church 11. mouth 12. family 13. tie 14. tomato 15. piano 16. baby 17. tooth 18. country 19. key 20 potato 21. match 22. box 23. hour 24. hero 二用冠词a, an, the 或 some , any 填空, 如果不需要,则用 / 代替. 1. Alice is ____ air-hostess. Her father is ____ engineer and her mother is _____ housewife. They all play ______ tennis very well. 2. He has ____ uncle and his uncle lives in ____ United Kindom. He first saw him in ____ autumn of 1978. 7. We need _____ ink, is there _____ left? 3. It is better to tell ______ truth than to tell _______ lies. 4. Will you have ______ more tea? There’s plenty in the pot. 5. There is ___university near my home. Every Saturday evening,___ students hold ____ party. ___ are dancing, ____ are singing. They make a lot of noise. 6. Get me ________ cigarettes, please. ______ kind will do. 三用适当介词填空. 1. Can you see the words written ________ the blackboard? (in, on, by, with) 2. She is taking the children out _______ a walk. (in, on, for, by) 3. You can choose the best one ________ them. (in, on, among, by) 4. Jack broke the chocolate _______ several pieces. (in, on, with, into) 5. There are two bridges ______ the river. ( in, on, with, into) 6. There is a slogan(标语) _______ the wall. (on, in, over, above) 7. He sits ________ his desk all day _______his head _______ his hands. He is deep in thought. (on, in, at, with) 8. _______ the help _______ the teachers, the students have made great progress _______their study. (on, in, of, with) 9. He will be back _______ a minute. ( on, in, for, by) 10. The teacher is standing _______ the class. (on, before, to, in) train arrived_____Shanghai_____6:30______a foggy November day .(on, in, at, by) 四用所给词的适当形式填空 1. Tom ______ (be) ill last week, he ______ (be) much better now. 2. Jimmy and his sister _______ (be) here several days ago. They ________ (leave) for Beijing yesterday. 3. He ___________ (have ) a bath when the telephone ________(ring). 4. While I __________ (cook ) the dinner, he ___________(read) the paper.