当前位置:文档之家› 2016年福建教师招聘《中学数学》真题解析

2016年福建教师招聘《中学数学》真题解析

2016年福建教师招聘《中学数学》真题解析
2016年福建教师招聘《中学数学》真题解析

2016年4月17日福建教师招聘

《中学数学》

一、单项选择题(10题,每题5分)

1.已知复数Z满足:(i为虚数单位),则z等于()

A.3/2–1/2i

B.3/2+1/2i

C.-1+3i

D.-1/2+3/2i

1.【答案】B.解析:,故选B.

2.已知集合A={X|y=√(1-x),x∈R},B={y|y=+2x-2},则A∩B等于()

A.Φ B.[-3,+∞) C.[-3,-∞) D.[-3.1]

【答案】D.解析:,

,选D.

3.下列命题错误的是()

A.对于任意的实数a与b,均有|a|+|b|≥|a+b|

B.存在a∈R,使得sin2a=2sina

C.存在a∈R对任意x∈R,使得<0

D.若(1+x)8=a0+a1x+a2x2+...a8x8,则a4>a5

【答案】A.对于A中不等式,当且仅当a、b符号相同时等号成立。

4.方程表示的曲线是()

A.两条射线

B.两个半圆

C.一个圆

D.两个圆

【答案】B.解析:方程可化为,且可得定义域为,即或且在是函数图像与

时对称,因为圆的圆心在(2,0)所以图像为两个半圆,选B.

5.已知函数f(x)=4-2nx+3在区间[-2,+∞)上是增函数,则f(1)的取值范围是()

A.f(1)≥23

B.f(1)=23

C.f(1)≤23

D.f(1)>23

【答案】A.解析:因为函数f(x)=4-2nx+3在区间[-2,+∞)上是增函数,所以函数的

对称轴,,故选A.

6.设是两个平面,可推得的条件是( )

A.存在一条知识

B.存在一条直线

C.存在两条异面直线

D.存在两条平行直线

6.【答案】C。解析:A显然不对只涉及一个平面。B项如果相交,,且a平行于

的交线,这时。D项如果相交,,如果a∥b并且平行于的交线,这时,。

7.若圆

+kx+my-4=0与直线y=kx+1交于M,N两点且M,N两点关于直线x+y=0对称,则不等式组

,所表示的平面区域的面积是()

A.1/4

B.1/2

C.1

D.2

【答案】A.

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