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2020上海徐汇二模高三英语试卷答案解析

2020上海徐汇二模高三英语试卷答案解析
2020上海徐汇二模高三英语试卷答案解析

2019年上海市徐汇区二模答案

一、选择题 1.在下列各式中,运算结果为x2的是() A.x4﹣x2B.x4?x﹣2C.x6÷x3D.(x﹣1)2 【分析】根据同类项的概念、同底数幂的乘除法法则、幂的乘方法则计算,判断即可.【解答】解:x4与x2不是同类项,不能合并,A选项错误; x4?x﹣2=x2,B选项正确; x6÷x3=x3,C选项错误; (x﹣1)2=x﹣2,D选项错误; 故选:B. 2.下列函数中,图象在第一象限满足y的值随x的值增大而减少的是()A.y=2x B.y=C.y=2x﹣3 D.y=﹣x2 【分析】直接利用一次函数以及反比例函数和二次函数的增减性进而分析得出答案.【解答】解:A、y=2x图象在第一象限满足y的值随x的值增大而增大,故此选项错误; B、y=,图象在第一象限满足y的值随x的值增大而减小,故此选项正确; C、y=2x﹣3图象在第一象限满足y的值随x的值增大而增大,故此选项错误; D、y=﹣x2,图象在第四象限满足y的值随x的值增大而减小,故此选项错误. 故选:B. 3.关于x的方程x2﹣mx﹣1=0根的情况是() A.有两个不相等的实数根B.有两个相等的实数根 C.没有实数根D.不能确定 【解答】解:△=(﹣m)2﹣4×1×(﹣1)=m2+4, ∵m2≥0, ∴m2+4>0,即△>0, ∴方程有两个不相等的实数根. 故选:A. 【点评】本题考查了一元二次方程ax2+bx+c=0(a≠0)的根的判别式△=b2﹣4ac:当△>0,方程有两个不相等的实数根;当△=0,方程有两个相等的实数根;当△<0,方程没有实数根.

4.今年3月12日,学校开展植树活动,植树小组16名同学的树苗种植情况如下表:植树数(棵) 3 5 6 7 8 人数 2 5 1 6 2 那么这16名同学植树棵树的众数和中位数分别是() A.5和6 B.5和6.5 C.7和6 D.7和6.5 【解答】解:∵植树数为3的有1人,植树数为5的有5人,植树数为6的有1人,植树数为7的有6人,植树数为8的有2人, ∴出现次数最多的数据是7, ∴众数为7; ∵一共有16名同学, ∴因此其中位数应是第8和第9名数据的平均数, ∴中位数为(6+7)÷2=6.5, 故中位数为:6.5. 故选:D. 5.下列说法,不正确的是() A. B.如果||=||,那么= C. D.若非零向量(k≠0),则 【解答】解:A、正确.∵=+,∴﹣=.不符合题意. B、错误.模相等的向量不一定相等,符合题意. C、正确.向量的解法返回加法交换律.不符合题意. D、正确.根据平行向量的判定得出结论.不符合题意. 故选:B. 【点评】本题考查平面向量的三角形法则,平行向量的判定,向量的加法交换律等知识,解题的关键是熟练掌握基本知识,属于中考常考题型.

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上海市2020届中考英语二模试题

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